# Find the area bounded by curve x² = 4y & line x = 4y-2 . Explain each step & the figure ,i m nt able to understand its figure

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by Mukss

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by Mukss

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X² = 4 y and x = 4 y - 2 ie.,, y = x / 4 + 1/2

area bounded by them... we find it by the integration..

the parabola x² = 4 y has axis as x = 0 ie., y axis. Focus is at (0, 1) and its vertex is at origin. It is like a U curve standing on the x axis at the origin.

The line intersects the x axis at (-2, 0) and y axis at the point (0, 1/2).

these two graphs intersect at :

x² = 4 y = (4 y - 2)²

=> 4 y² - 5y + 1 = 0

=> y = 1 or 1/4

=> x = 2 or -1

Thus we have to find the area bound between the two curves between the points (2,1 ) and (-1, 1/4).

we know that the straight line is above the x axis when it cuts the curve. y1(x) is the line. and y2 (x) is the parabola.

area bounded by them... we find it by the integration..

the parabola x² = 4 y has axis as x = 0 ie., y axis. Focus is at (0, 1) and its vertex is at origin. It is like a U curve standing on the x axis at the origin.

The line intersects the x axis at (-2, 0) and y axis at the point (0, 1/2).

these two graphs intersect at :

x² = 4 y = (4 y - 2)²

=> 4 y² - 5y + 1 = 0

=> y = 1 or 1/4

=> x = 2 or -1

Thus we have to find the area bound between the two curves between the points (2,1 ) and (-1, 1/4).

we know that the straight line is above the x axis when it cuts the curve. y1(x) is the line. and y2 (x) is the parabola.