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Naming the quadrilateral abcd give the intersection of the diagonal O as ac=10 therefore AO=5 and also aob is a right angle tri. ob=hypo.. therefore ob^2=ab^2 +ao^2 therefore ob=5root 2 now cod is a right angle therefore od^2=cd^2-co^2 therefore od^2=17.25
length of diag. =4.15+ 5root2 =11.22
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Length of the diagonal= ob +od applying pytha. to aob therefore ob =5root2 now applying pytha. to cod therefore od =4.15 total length f the diagonal =11.22
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