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Too easy yaar first we have twoo roots √3 and -√3 right we can write them as (x-√3) and (x+√3) mulitply both these to get a polynimial it is in the form of (a+b) and (a-b) = a²-b² this == x²-3 Now divide the polynomial x⁴-5x³+3x²+15x-18 with x²-3we get quotient as x²-5x+6 on factorising it we get factors 3 and 2 Therefore answer is √3,-√3,3 and 2 Hope my answer is helpful Please mark it as brainlest

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Two zeroes are √3 and -√3 So two factors are (x-√3) and (x+√3)

(x-√3)(x+√3) = x² - 3 x² - 3 is a factor of x⁴-5x³+3x²+15x-18

Now. divide x⁴-5x³+3x²+15x-18 by x²-3 You will get (x² - 5x + 6)

Now find the zeroes of x² - 5x + 6 = 0 ⇒ x² - 5x + 6 = 0 ⇒ x² - 2x -3x + 6 = 0 ⇒ x(x-2) -3(x-2) = 0 ⇒ (x-3)(x-2) = 0 ⇒ x-3 = 0 and x-2 = 0 ⇒ x = 3 and x=2