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log__{ \sqrt{3} }}  \sqrt[3]{3} = \frac{log_3  \sqrt[3]{3} }{log_3  \sqrt{3} } = \frac{log_3  3^{1/3} }{log_3 3^{1/2}} = \frac{1/3}{1/2} = \frac{1}{3} \times  \frac{2}{1}  =\boxed{ \frac{2}{3} }
1 5 1
It is not divided by root3 . It is base . Which formula of log is used here?
log C base b = (log C base d)/(log b base d)
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