Answers

2014-06-24T18:47:35+05:30
Using eqn:-

S=ut+ \frac{1}{2} a*t^{2}

here,u=initial speed=0;
a=g=9.8  \frac{m }{sec^{2}}
S=4.9 m

i.e. 4.9 = 0.t +1/2*9.8* t^{2}

 \frac{4.9}{4.9}= t^{2}[tex]

1=t^2

i.e t=1sec. 
1 5 1
finally after confusion i hv done dis...
yes now its absolutely correct
thanks
i m puzzled in the ques.