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2014-06-25T07:00:57+05:30

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Let the sum of rupee be x and no of boys be y then each boy get x/y now if the no of boys increased by 10 each boy get x/(y+10) = (x/y)-1 => x/(y+10) = (x-y)/y ............,.(1) now case 2nd if no of boys decrease by 15 each boy get x/(y-15)= (x/y) +3 => x/(y-15) = (x+3y)/y ...........(2) solve the equations and get the answer
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2014-06-25T23:04:23+05:30

This Is a Certified Answer

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Let the sum of rupee be x
 no of boys be y
then each boy get x/y
now if the no of boys increased by 10 each boy get x/(y+10) = (x/y)-1 => x/(y+10) = (x-y)/y .........(1)
now case 2nd if no of boys decrease by 15 each boy get x/(y-15)= (x/y) +3 => x/(y-15) = (x+3y)/y ...........(2)
solve the equations and get the answer
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