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2015-10-26T13:58:08+05:30
1 bar is approximately equal to 1 atm.

At Const. Temp.
P_{1}V_{1}=P_{2}V_{2}
V_{2}= P_{1}V_{1}/P_{2} = 175 × 1/0.8 = 218.75mL
      





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2015-10-26T14:27:41+05:30
V1=175,p1=1bar,v2=?p2=0.80atm Therefore, By Boyle's law, P1v1=p2v2 =p1v1/p2 =1*175/0.80 =218.75L
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