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A child purchases a number of notebook for rs 80. If he had purchased 4 more notebooks for the same amount from the other bookseller , then a notebook

would have cost rs 1 less. Represent the above situation in the form of quadratic equations .


Assume that no. of books be n,price of books be p from first condition np=80 from second condition (n+4)(p-1)=80 From first and second condition, np=(n+4)(p-1) np=np+4p-n-4 n+4=4p But p=80/n n+4=4×80/n n^2+4n-360=0
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