Answers

2015-10-25T20:42:45+05:30
Ans : y=30x-10__________________ Procedure : given that no. of hours is x, total fare is y. For first 3 hours fare is 80 , after 3 hours the fare is 30×(x-3) So y=80+30(x-3) y=80+3x-90 y=3x-10
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2015-10-25T21:46:28+05:30
Let the number of hours be = x
let the fare be=y

A/Q for first 3 hours fare =rs 80
and then for every consecutive hours fare =rs 30

therefore equation is y=30(x-3)+80
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