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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Let the no of toys be x and price of each toy be y therefore, xy = 360 and x=360/y {eg -1} 2nd condition (x+2)(y-2)=360 xy + 2y - 2x - 4 = 360 2y - 2(360/y) - 4 = 0 { since xy=360 & from eq 1} - 4y -720 = 0 - 2y - 360 =0 - 20y +18y -360 =0 y(y-20) +18(y-20) = 0 (y+18)(y-20)=0 therefore y= -18 or y = 20 in this case y=20 since price of quantity cannot e in negative therefore the original price of toy is 20 rupees

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