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Finding the root by completing square method
for this let us take a quadratic equation ax^2+bx+c=0
step 1 :-
Reduce the coefficient of x^2 to 1
step 2 :-
now add and subtract the square of the half of the value
step 3 :-
now make the formula of either (a+b)^2 or (a-b)^2 according to the equation
[x^2+(b/a)^2+(b/a)] - (b/2a)^2+c/a
step 4 :-
after making the formula add the remaining digits and try to write them in the term of their perfect square
[x+(b/a)]^2 +[c/a+(b/2a)^2]
on solving
[x+(b/a)]^2+ [sqrt(c+b^2)/sqrt(2a)]=0

finding rooys of square by firmula method
let us consider a quadratic equation ax^2+bx+c


Hope it helps

0 0 0
b/a wale coefficient ke sath x bhi hai aur aur main x ke coefficient ki bat kar raha hu in step 2.plz don't mind
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