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the answer is option (b) 4u^2/g
2gh= v^2-u^2
2gh = (3)^2-(u)^2
2gh = 9u^2 -u^2
2gh = 8u^2
gh = 8u^2/2
h = 4u^2/g
therefore the answer is, (b)
 i hoe that this will help u..........................^_^

2 5 2
U have to mention that...
ye to mention hai ki initial velocity u hai
Mention kiya h ki initial velocity u se niche nahi fekaa h uper feka h
The speed of the stone upwards, is the same when the stone falls back to the same height... ie., at the edge of the cliff..
the stone travels up at 10m/s vertical component, then it becomes 0.. when it falls down, it regains the same speed at the same altitude..
you must mention this point in the answer
Not 10m/s ***u
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