the foot of a ladder is 6m away from a wall and it's top reaches a window 8m above the ground if the ladder is shifted in such a way that it's foot is 8m away from the wall. So what height does it's top reach?

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Let A be the foot of the ladder. B be the top of the ladder. C be the junction/corner of the wall and floor. AB = 6m, BC = 8 m... When AB = 8m.. Then BC becomes 6m., The sides AB and BC are interchanged, as the length AC is constant.

Answers

2015-10-30T11:16:13+05:30

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The 'ladder', 'height to which it reaches' and 'foot of ladder from wall' forms a right angled triangle.
ladder = hypotenuse(h)
height to which it reaches = base(b)
foot of ladder from wall = altitude(a)

initially, a = 8m, b = 6m
h² = a² + b²
⇒ h = √(a²+b²) = √(8² + 6²) = √100 = 10m

when foot is 8m away from wall,
b = 8m, h = 10m, a = ?
h² = a² + b²
⇒ a² = h² - b²
⇒ a = √(h² - b²) = √(10² - 8²) = √36 = 6m

So its top reaches 6m height
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2015-10-30T11:36:20+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
6 Metres

6m sq + 8 m sq=x m sq
100 m = x m sq
x= 10 m= length of ladder

base= 8 m length of ladder= 10 m 
therefore height from ground to top = uder root of( 10 m sq - 8 m sq)= 6METRES
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