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The sum of the digits of a two digit number is 10 if we reverse the digits the new number will be 54 more than the original number what is the original



The original no is 28
solution :-
let digit at tens place be x
the digit at ones place be y
the original no be 10x + y
and 10y + x is digit are reversed
so, x + y = 10 .....(i)
10y + x - (10x + y) = 54
 y - x = 6
by adding both the eq.
we will get y = 8
then by putiing  y = 4 in eq. (i)
x = 2

1 5 1
Hi there,
let number be 10x+y
therefore x=10-y=2
therefore the original number =20+8=28
i hope this ans helps u...

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