Answers

2015-10-31T13:00:48+05:30
Please refer to the image.

Hope it helps...!
1 5 1
wait i m editing it
ok
answered ot 75 N
ok
right now ??/
2015-10-31T15:39:42+05:30
M = 3kg
M = 5kg

a = (M-m)/(M+m) * g
  = (5-3)/(5+3) * 10
  = (2/8) * 10
  = 2.5 m/s²

Tension in the string attached to the masses
T = mg + ma
  = m(g+a)
  = 3(10+2.5)
  = 37.5N

Tension in the upper string,
T' = 2T = 37.5*2 = 75N
1 5 1
its for class 8...I am studying like this type of problems in 9
this is class 11th course in cbse..I don't know how did the question come to class 8th!!