# An electric cable cost Rs 200.If the cable was 3m longer and each meter of cable costs Rs 2 less,the cost of cable would have remained unchanged.Represent the above situation in the form of a quadratic equation

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Let the length of the cable = L meters

the cost of the cable = 200 / L Rs/meter

given ( L + 3) * (200/L - 2) = Rs 200

200 - 2 L + 600/L - 6 = 200

simplifying

* L² + 3 L - 300 = 0*

L = [-3 +- √1209] /2 = 15.885 meters

cost of the cable = 12.59 Rs/m

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in terms of the cost of the cable:

Let the cost of the cable be : C Rs/m

So length of the given cable: 200 / C

given: (200 / C + 3) (C - 2) = 200

200 - 400 / C + 3 C - 6 = 200

3 C² - 6 C - 400 = 0

the cost of the cable = 200 / L Rs/meter

given ( L + 3) * (200/L - 2) = Rs 200

200 - 2 L + 600/L - 6 = 200

simplifying

L = [-3 +- √1209] /2 = 15.885 meters

cost of the cable = 12.59 Rs/m

=============

in terms of the cost of the cable:

Let the cost of the cable be : C Rs/m

So length of the given cable: 200 / C

given: (200 / C + 3) (C - 2) = 200

200 - 400 / C + 3 C - 6 = 200

3 C² - 6 C - 400 = 0

the cost of the cable = 200 / x Rs/meter

given ( x + 3) * (200/x - 2) = Rs 200

200 - 2 x + 600/x - 6 = 200

by simplifying

x = [-3 +- √1209] /2 = 15.885 meters

cost of the cable = 12.59 Rs/m

in terms of the cost of the cable:

Let the cost of the cable be : C Rs/m

So length of the given cable: 200 / C

given: (200 / C + 3) (C - 2) = 200

200 - 400 / C + 3 C - 6 = 200

3 C² - 6 C - 400 = 0