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2015-11-01T12:16:22+05:30

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Sum of an arithmetic series for the first n terms = [2a + (n-1) d] n /2

sum of the even page numbers :    see that there are 60 of them.
     2 + 4 + 6 + 8 + .... + 120
   = [ 2 * 2 + (60 - 1) 2] * 60/2 = 3660

sum of the odd page numbers:  (there are 120 - 60 = 60 numbers)
   = 1 + 3 + 5 + 7 + .... + 119
   =  [ 2 * 1 + (60 -1) 2 ] * 60/2  = 3600


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