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A disc of weight 200 newton and radius 4 cm.A rectangular bar of dimensions 5×4×3cm of weight 110 newton.A cube of esge 5cm and weight 120 newton,are

placed on a table.If P1,P2andP3 are the pressures exerted by respectively then compare P1,P2 and P3



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Pressure exerted by an object through its base :
       weight in Newtons / surface area of its base in contact with the table.

Pressure due to the disc : P1  =  200 N/ π 0.04²  m²
                             bar:    P2  =  110 N / (0.05 * 0.04 m²)          
                            cube:   P3  =  120 N / (0.05 * 0.05 m²)

To convert the pressure in  to dynes,  multiply by 10⁵.

Compare:  P1 : P2 : P3  =   25  :  11 π  :  9.6 π

1 5 1
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