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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Let cost of 1 chair be Rs. x cost of be table be Rs. y According to the question, cost of 4 chairs and 3 tables is Rs. 2100 So, 4x + 3y = 2100 ……...... (i) Also, cost of 5 chairs and 2 tables is Rs.1750 So 5x + 2y = 1750 ……….. (ii) from equation(i) and (ii) 2 × (i) gives8x + 6y = 4200 ……… (iii) 3× (ii) gives15x + 6y = 5250 ……….. (iV) {(iii) -(iV)} , 15x + 6y – 8x – 6y = 5250 – 4200 7x = 1050 x=1050/7 So, x = 150 putting the value of x in equation (ii), we get ⇒ 5(150) + 2y = 1750 ⇒750 + 2y = 1750 ⇒2y= 1750 – 750 ⇒2y = 1000 ⇒y =1000/2 ⇒ y =500 Hence, cost of each chair,x = Rs. 150 cost of each table,y = Rs. 500