Answers

2015-11-13T01:12:38+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Volume = V = 2 L = 0.002  m³
T = 273.15 + 27 = 300.15 °K
R = 8.314 J/ mole / °K

number of Moles of Oxygen  = 10 gm / 32 gm/mol  = 5/16
number of moles of Hydrogen:  8 gm  / 2 gm/mol = 4
total number of moles in the gas mixture = 69/16

P V = n R T
P = 69/16 * 8.314 * 300.15 / 0.002      Pa
   = 53.8 atm  approximately    or   5.38 * 10⁶ Pa

It seems a lot,  for just 18 gms of a gas mixture in a 2 L container at room temperature, exerting  5 times atmospheric pressure.
1 5 1
click on thanks button above;; select best answer