Answers

2015-11-03T20:24:40+05:30
He divided his money in ratio 5:3
let the money by younger child be y and the elder child be e.
∴e/y = 5/3
e / 156 = 5/3
e = 156 × 5/3 
e = 260
therefore the money received by the elder child is 260.

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2015-11-03T23:24:45+05:30
Let the two parts of money of Mr. Cooley be 5x and 2x
A/q,
The younger child gets the smaller amount => 2x =156
                                                               => x = 78
So, the amount got by the older child = 5x = 5(78) = 390
Therefore, the older child got Rs. 390

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