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He divided his money in ratio 5:3 let the money by younger child be y and the elder child be e. ∴e/y = 5/3 e / 156 = 5/3 e = 156 × 5/3 e = 260 therefore the money received by the elder child is 260.

Let the two parts of money of Mr. Cooley be 5x and 2x A/q, The younger child gets the smaller amount => 2x =156 => x = 78 So, the amount got by the older child = 5x = 5(78) = 390 Therefore, the older child got Rs. 390