Free help with homework

Why join Brainly?

  • ask questions about your assignment
  • get answers with explanations
  • find similar questions

A straight line, AB, undergoes two reflections. First reflection occurs in a mirror, placed in the vertical plane at x=0. The reflected line undergoes

another reflection, in another mirror, placed in the horizontal plane at y=0. If the x and y intercepts of line AB are p and q respectively before the reflections, then the equation of the line after the second reflection will be:


The x and y intercepts of the unreflected ray are (p,0) and (0,q).
therefore the equation of the line(ray) before reflection is

(x/p) + (y/q) = 1
qx + py - pq = 0

now as the ray is getting reflected two times, first on the y-axis and then on the x-axis, the slope of the line remains unchanged.
therefore the equation of the line will become

qx + py + c = 0 where c is just a constant
now after the second reflection the x intercept of the line becomes (-p,0)
-pq + 0 + c = 0 therefore c = pq

therefore the equation of the second line becomes

qx + py + pq = 0

0 0 0
The Brain
  • The Brain
  • Helper
Not sure about the answer?
Learn more with Brainly!
Having trouble with your homework?
Get free help!
  • 80% of questions are answered in under 10 minutes
  • Answers come with explanations, so that you can learn
  • Answer quality is ensured by our experts