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SinC =15/17 = opposite/hypotenuse
CosC= Adjesent /hypotenuse
In tri.ABC
AC°2 =AB°2+BC°2
17°2=15°2+BC°2
289=225+bc^2
BC°2= 64
BC=8
CosC=8/17

### This Is a Certified Answer

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*Given :- sin c = 15/17*

*But we know that, sin θ = p/h = perpendicular/ hypotenuse*

*Therefore, p = 15 and h = 17*

*By Pythagoras Theorem,*

*h² = p² + b²*

*(17)² = (15)² + b²*

*289 = 225 + b²*

*289 - 225 = b²*

*b² = 64*

*b = √64*

*b = √8 * 8*

*b = 8*

*So, cos θ = b/h*

*Therefore, cos c = 8/17*