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An elevator descends into a mine shaft at the rate of 5 metre per minute.What will be its position after one hour? If it begins to descend from 15 m above

the ground, what will be its position after 45 minutes


1 minute=5 metres. So 1 hour (60 mins)=60×5=300metres. It started 15 metres above the ground.so the present position under the ground=300-15=285metres. So the elevator is 285metres under the ground. Hope this helps you
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An elevator descends into mine shaft at the rate of 5 meter per minute.
so for 1 min elevator descends 5metres.
the position of the elevator after one hour =
we know 1 hour =60 min so 60min x 5metres=300 meters..
but the elevator began to descend from 15 meters above so,
and its position after 45 mins is 45metres x 5 mins=225 meters.
 and the elevator has descended from 15 meters above so
225-15 meters="210metres."

hope this helps u.

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