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2015-11-09T20:08:52+05:30

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I = 5 A    Resistance = R
I' = 4 A    R' = R+2  Ω     = total resistance

We assume R is the total effective resistance in the circuit in series with the battery.  Also, that 2 Ω resistance is added in series with the= given resistance and battery.

   Voltage of the battery = E = I R = I' R'
     5 * R = 4 ( R +2)
     =>  R = 8 Ω
 
   battery potential is =  40 V

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2015-11-09T20:10:29+05:30

This Is a Certified Answer

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
First pls type the complete question , In complete question , it has been said that V is same , so ,

Ohk then let R is the original resistance then ,

V/R = 5 & V/R+2 = 2

Dividing ,

R+2/ R = 5/4

R = 8 ohm
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