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2015-11-11T11:34:07+05:30

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Cot(15)=1/tan15
tan(45-30)
we know that tan(A-B)=tanA-tanB/1+tanAtanB
1-1/√3/1+1/√3
√3-1/√3+1
on rationalization
√3 - 1     . √3-1
√3 +1      √3-1
3+1-2√3/3-1=4-2√3/2⇒2-√3
cot 15=1/tan 15=1/2-√3
again rationalize
1      .2+√3
2-√3  . 2-√3
2+√3/4-3⇒2+√3



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come on chat box,there we can discuss this
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haha, where can i find the chatbox?sorry im new~XP
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