Answers

2015-11-15T15:45:46+05:30
Let us resolve the components of forces along the positive x-axis = East... and  positive y-axis ie., North.

   F_x = 20 Cos 30⁰  - 30 Cos 45⁰ - 35 Cos 40⁰  Newtons
         =  - 30.704 Newtons in the direction of  West...

  F_y =  25 + 30 Cos (90-45)  - 35 Cos (90-40)
          = 23.715  Newtons  towards  North.

Resultant is =  [tex]\sqrt{F_x^2+F_y^2}=  38.796  Newtons 
direction is :  Ф deg. North of West 
     Tan Ф =  | F_y /  F_x | =  23.715 / 30.704 = 37.68 deg. 
1 5 1