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Principal=12000Rs Let rate of interest be r Therefore, principal after 1 year1200(1+r/100)-4000 Compound Interest for 2nd year is 920 Therefore, {12000(1+r/100)-4000+920} (1+r/100)={8920+120r}/{8000+120r} r/100=920/8000+120r 120r2+8000r-92000=0 Solving above equatn we get, (3r+230)(r-10)=0 since, interest can't be -ve so, rate of Interest=10%