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A cylindrical jar of cross sectional area of 50cm^2 is filled with water to a height of 20cm. it carries a tight-fitting piston of negligible mass. the

pressure at the bottom of the jar when a mass of 1kg is placed on the piston (ignore atmospheric pressure, given:g=9.8)

Area A = 50 cm^2 = 50 /10000 m^2 = 0.005 m^2 height = 20 cm = 0.20 meter

Pressure due to atmospheric air = 1.013 * 10^5 Pa = 101,300 Pa Pressure on the surface of water = by the mass of 1kg = weight of 1kg/area of piston = 1 kg * 9.8 m/sec² / 0.005 m^2 = 1,960 Pa

Pressure due to the water column (depth) of water at the bottom of the jar = weight of water column / area of cross section = ρ g h (ρ is the density ) = 1000 kg/m³ * 9.8 m/sec² * 0.20 m = 1,960 Pa

If we Ignore atmospheric pressure it is: 3, 920 Pa but if we count the atmospheric pressure: then 105, 220 Pa