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A force of 5N acting on a body at a angle of 30 degree with an horizontal direction displaces it horizontally through a distance of 6m .Calculate the work

done .



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force = 5 N
angle formed = 30°
displacement = 6 m
therefore work done ,
= F*s*cosθ
= 5 * 6 * cos (30)
= 30 * 0.866...
= 25.98 J
therefore work done = 25.98 J
  i hope that it will help u..............................^_^
2 4 2
ur welcome 
btw u r in which class??
9 th
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