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Three uniform spheres each having m and radius r are kept in such a way that each touches the other. find the magnitude of the gravitational force on any

sphere due to the other two. ans. \sqrt{3of GM^2/4R^2


Force between two spheres will be $F= \large\frac{GMM}{(2R)^2}=\frac{GM^2}{4R^2}$ Two forces of equal magnitude are acting at angle $60^{\circ}$ on any of the sphere $F_{net}=\large\frac{\sqrt 3}{4} \frac{GM^2}{R^2}$ Hence a is the correct answer.  
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please answer clearly i cant understand this language
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