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A particle has shifted along some trajectory in xy plane from point r1=1i-2j to another point r2=2i+3j during that time, the particle experiences the

action of two forces F1=3i+4 and F2=2i-7j.the work done by the forces on the particle will be ?


The answer should be 5√10.
Get the final displacement by r1 - r2.
Now add f1 and f2 by vector addition method.
Multiply both results by applying Dot product of vectors and find their magnitude.
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