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Hi there,

area of square =4 so by Pythagoras theorem the diagonal =√8=radius area of the circle=πr^2=25.132 i hope this helps u...

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the area of the square = 4 therefore length of each side is , area = side *side 4 = side *side 2*2 = side *side therefore length of 1 side = 2 diagonal of a square = side * √2 = 2 √ 2 A.T.Q , diagonal of square = radius of the circle area = πr² area = 22/7 * 2√2 * 2√2 area = 22/7 * 2 * 2 * 2 area = 22/7 * 8 area = 25 .132 therefore the answer is 25.132 i hope that this will help u.....................^_^

length of each side is 2

by pythagoras theorem....diagonal length is \sqrt{8}

radius = \sqrt{8}

area of circle = \pi r^{2}

25.132