Two bullets P and Q,masses 10 g and 20 g,are moving with the same distance towards the target with velocities 20 m/s and 10 m/s.Which one of the bullets will pierce a greater distance from the target.

The answer is P. Plzz tell me the solution with formula and how

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anyways i live in assam
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i live in assam
nd u ?
I live in Maharashtra,Mumbai

Answers

The Brainliest Answer!
2015-11-16T15:50:51+05:30
mass of P = 10 g = 10 / 1000 = 0.01 kg
velocity of P = 20 m/s
initial of P = 0 m / s
mass of Q = 20 g = 20 / 1000 = 0.02 kg
velocity of Q = 10 m/s
initial of Q = 0 m / s 
acceleration of P and Q = 10 m / s
distance of P ,
2as = v
² - u²
2 * 10 * s = 20
²- 0²
20 * s = 400
s = 400 / 20 
s = 20 m
distance of Q ,
2as = v
² - u²
2 * 10 * s = 10
² - 0²
20 * s = 100
s = 100 / 20
s = 5 m
therefore the answer is P .
    i hope that my answer will help u ..............................^_^ 
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