Answers

2014-06-29T19:23:01+05:30
V=58km/h
u=56km/h
t=1sec or 1/60h
a=(v-u)/t
a=(58-56)/(1/60)
a=2x60/1
a=120km/h
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2014-06-29T19:29:59+05:30
Initial speed = 56 km/hr = 56×1000÷3600=15.5 m/s  {u}
final speed   = 58 km/hr = 58×1000÷3600=16.1 m/s  {v}
acceleration =  \frac{v-u}{t}
                   =  \frac{16.1m/s - 15.5m/s}{1s}
                   =0.6 m/s²
          therefore acceleration is 0.6m/s²
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