Answers

2015-11-17T22:00:42+05:30
IN THE ADJACENT FIGURE
DECF IS ARECTANGLE SO DE=CF⇒1
AS,DC||Ab,AB IS A TRANSVERSALSO ANGLE AED=ANGLEBFC⇒2GIVEN AD=BC⇒3
FROM1,2,3
BY RHS congruency
triangleAED=TRIangleDFC
BY CPCT
AE = BF
1 5 1
2015-11-17T22:02:51+05:30
IN THE ADJACENT FIGURE
DECF IS A RECTANGLE SO DE = C ---(i)
AS,DC||AB
AB IS A TRANSVERSE
 ALSO ∠AED = ∠BFC ---(ii)
GIVEN AD=BC ---(iii)
FROM (i), (ii) and (iii)
BY RHS congruency
ΔAED = ΔDFC
BY CPCT
AE = BF
1 5 1