An aeroplane flying horizontally at an altitude of 490 m with a speed of 180 kph drops a bomb.the horizontal distance at which it hits the ground is
(A)500m
(B)1000m
(C)250m
(D)50m
Please answer with explination

1
shymasneha are u sure that these are the only options?........just asking 
in option (C) it is 250 m i think it should be 2450 m ? 
sorry i was wrong all the options are correct :) 
and the answer is option is (A) 

Answers

2015-11-18T14:32:41+05:30

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given,
speed of the airplane = 18 kph = 50 m/sec
it's altitude = 490 meter 
1st of all we have to find out the time to travel 490 meter ,
now,
s = ut + 1/2 at²
490 = 0 * t + 1/2 * 9.8 * t²
490 = +4.9t²
490/4.9 = t²
100 = t²
10 = t
therefore time time taken to travel 490 meter = 10 sec
therefore now , 
horizontal distance = time taken * speed 
distance = 10* 50 
distance = 500 meter .
therefore the answer is 500 meter and the correct option is option(A) that is 500 m .
           i hope it helps........................^_^ 
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