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2015-11-20T20:40:00+05:30
As per the question 
R1 = R, R2 = 2R
NOW THE INITIAL WORK DONE (W) IS = 8πR²s
and FINAL WORK DONE (W)= 8π[R2² - R1²]s
8π[4R² - R²]S
3 x 8πR²s  =  so W = 3W AS THE W IS EQUAL TO 8πR²S
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