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How much did Morrison receive for each ring? Professor Morrison sold a total of three precious rings on the black market for $1,750. Holmes was able to

trace all three rings and found that Morrison had sold off the second ring for $50 more than the first one, and the third ring for $600 less than the second one. How much did Morrison receive for each ring?


Let the selling price of the 1st ring be $ x.

So, the Price of 2nd ring= $(x+50)

And the price of 3rd ring=&(x+50-600)=$(x-550)

Also total price=$1750

∴ x+x+50+x-550=1750

∴Price of 1st ring=x= $750
Price of 2nd ring=x+50=750+50= $800
Price of 3rd ring=x-550=750-550= $200
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