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A body of mass 2kg is dropped from the top of a tower of height 50m .If the acceleration due to gravity is 10m\s^2, what will be it's kinetic energy at the

end of 2s.


For a freely falling body,

where g is acceleration due to gravity and t is time.
g=10 m/s²

So v=10*2
       = 20 m/s

(Thus in 2s body would travel a distance of 40 m from release point)
Kinetic Energy K=1/2 mv²


So K= 1/2 * 2 *20²
        = 1 * 400
        = 400 J

Thus the Kinetic Energy of the body would be 400 J at the end of 2s.
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