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1.if (2,1)(4,5)(-1,-3)are the midpoints of the side abc. find the coordinate of the vertices abc

2.determine the perimeter of the triangle whose vertices are (3,2) (7,2)(7,5)
3.find the equation of the line passing through (1,2)and parallel to 4x+5y+3=0



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1.let A(x1,y1)
now applying midpoint theorem,
x1 +x2=4,
x2+x3=8,and x1 +x3= -2
solving ,
x1= -3, x2= 7 , x3= 1
similarly, y1= -7, y2=9 and y3= 1
so points are A(1,-7), B(7,9) , C(1,1)
2. perimeter of triangle will be AB +BC +CA
by distance formula,
AB= 4, BC =3 and CA=5
so perimeter = 12 unit
3.equation of line parallel to 4x+5y+3=0 will be 4x+5y+c=0,
putting the value (1,2), 
c= -14
so the equation of line will be 4x+ 5y -14=0

hope u got the answer :)
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