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1.since line is parallel to 2x+54+y=0, so the equation will be 2x+y+c=0 Now point (4,-3) lie in this line, so,c= -5 hence equation of line is 2x+y-5=0 2. we can use distance formula to find the length of sides and then area= 1/2(base×height)

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

1. equation given 2x-5y +4 =0 a=2 ,b=-5 , c=4 we know that equation of any line perpendicular to ax+by+c =0 is bx-ay +k =0 -5x -2y +k =0 passes through (4 ,-3) -5(4)-2(-7)+k=0 -20+6+k =0 k =14 required perpendicular line is -5x-2y+14 =0