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A Cylindrical tub of radius 12cm contains water upto depth of 20cm. a spherical iron ball is dropped in the tub and the level of water increases by 6.75cm.

what is the radius of the ball?


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Volume increase = volume of sphere
π×R²×H = 4/3π ×r³
(12)²× 6.75=4/3 r³
solving we get,
radius r= 9 cm
hope u get the answer :)
2 5 2
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