Answers

2015-11-29T21:16:58+05:30
Mass of boron as given = 0.096 g
 Mass of oxygen as given = 0.144 g
Mass of sample as given = 0.24 g
Percentage of boron by weight in the compound = (0.096 ÷ 0.24 ) x 100 = 40%
Percentage of oxygen by weight in the compound = (0.144 ÷ 0.24) x 100 = 60%
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2015-11-30T21:20:01+05:30
Oxygen-60 nd boron 40 precent
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