Answers

2014-07-03T13:08:21+05:30
A rhombus have all the lines equal. AB=BC=CD=DA

AB= rad [(1-5)^2+(0-3)^2]
AB= rad [(-4)^2+(-3)^2]
AB= rad 16+9
AB= rad 25
AB=5

BC= rad [(5-2)^2+(3-7)^2]
BC= rad [3^2+(-4)^2]
BC= rad 9+16
BC= rad 25
BC=5

CD= rad [(2-(-2))^2+(7-4)^2]
CD= rad [(2+2)^2+(-3)^2]
CD= rad (4^2+9)
CD= rad 16+9
CD= rad 25
CD=5

DA=rad [(-2-1)^2+(4-0)^2]
DA= rad [(-3)^2+(4)^2]
DA= rad 25
DA=5

SO, AB=BC=CD=DA=5 => ABCD rhombus
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