Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Ten circles of equal radius are arranged as follows.Four circles are arranged in a row side by side touching one another.Three circles are arranged in the

same way but on the four circles.Two circles are arranged on the three circles and the remaining one circle is arranged above the two circles.If r is the radius of each circle,then the height of the last circle i.e. top circle from the horizontal ground is. A:(2+2√3) B:(2+3√3) C:(1+3√3) D:2√3

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

see, when you arrange all the circles, the line joining centre will form a equilateral triangle. so, side length =6r half of side is 3r now, applying pythagoras theorem, height= √((6r)²-(3r)²) =√(36r²-9r²) =√(27r²) height = 2r√3