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ABC is a isoscles triangle in which AB parallel AC . AD bisect exterior angle and CD parallel AB ( see fig 8.4 )show that. (1) angle DAC = angle BCA (2)

AB parallel to AC, how????
AB is not parallel to AC.It is actually equal to AC.



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∠ACB+ ∠ABC= ∠CAP ( exterior angle is equal to sum of opp. interior angles)
so, ∠CAP= 2 ∠ACB =2ABC
∠CAP= 2∠CAD= 2∠DAP
so, ∠ACB=∠CAD 
but they are alt interior angles
so, AD parallel to DC

hence ABCD is a parallelogram
1 5 1
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