A capacitor of capacitance C is charged with the help of a 200V battery. Its then discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity 2.5 x 10 2 J/kg and mass 0.1 kg. If the temperature of the block rises by 0.4K, the value of C is a) 500 F b) 500 x 10 -6 F c) 50 F d) 50 x 10 -6 F

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2015-12-11T22:17:12+05:30

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The answer of ur question is
 500 x 10 -6
for solution
see the photo
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2015-12-12T19:37:49+05:30

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The heat gained by the block             Q = mCvdt                                                                                                                       = 0.1*250*0.4                                                                                                               = 10 J
Energy stored in a capacitor is ½ Cv^2
                                  10 = ½ c (200)^2  
                                    C= 500 * 10^-6 F
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