Answers

2015-12-10T21:50:50+05:30
We know that:-
[secA^2-tanA^2=1]
(secA^2-tanA^2)=1
(secA+tanA)( secA-tanA)=1
(secA+tanA)*1/3=1     [secA-tanA=1/3]
(secA+tanA)/3=1
(secA+tanA)=3
(secA-tanA)=1/3
By simultenous equation we get:-
tanA=4/3
secA=5/3




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