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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Two taps together can fill a tank in 9 3/8 hrs. D tap of larger diameter takes 10hrs less the smaller one to fill the tank separately. Find the time in

Let the time taken by the tap of larger diameter be x hrs. ,, ,, ,, ,,,, ,, ,, ,, ,, smaller diameter be y hrs. ATQ.... 1.) x+y=9 3/8 2.) x=y-10 x-y=-10 Sub. 1 & 2 , we get, y=9.6875 hrs

Let the time taken by the two taps separately be x hrs and (x+10) hrs . total time = 9 3/8 = 75/8 hrs . according to the problem , 1/x + 1/(x+10) = 8/75 x+10+x/x(x+10) = 8/75 2x+10/ x2 +10x = 8/75 8(x2+10) = 75(2x+10) 8x2+80x = 150x + 750 8x2 -70x -750 =0 4x2 -35x -375 =0 (x-15)(4x+25) =0 if (4x+25) =0 x =-25/4 is rejected because time will not be in negative . if (x-15) =0 x =15 x =15 & x+10 = 15+10 =25 therefore , time taken by the two taps separately are 15hrs & 25hrs . HOPE it helps !